sql – 按字母顺序查询名称的查询

我使用了LIKE条件,但它要求我在数据库中输入全名来查找名称.

if (searchby.equals("Name"))
{
    try
    {
        Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
        System.out.println("\n Driver loaded");
        Connection con=DriverManager.getConnection("jdbc:odbc:wanisamajDB");
        Statement stmt=con.createStatement();
        ResultSet rs = stmt.executeQuery("SELECT Name FROM FAMILYcensus WHERE Name LIKE '"+ tfsearch.getText()+"'");
        //  ResultSet rs = stmt.executeQuery("SELECT Name FROM FAMILYcensus WHERE Name LIKE );
        System.out.println("Hi");

        rs.next();
        String names = rs.getString("NAME");
        System.out.println("NAME: " + names );

        JOptionPane.showMessageDialog(null,"RECORD FOUND");

        tasearch.setText(names);
    }
    catch (Exception e)
    {
        System.out.println("EXCEPTION " + e);
    }

解决方法

WhiteFang34还说你需要迭代.但是您还需要更改为WHERE子句：

"SELECT * FROM FAMILYcensus WHERE Name > '"+ tfsearch.getText()+"' ORDER BY Name ASC LIMIT "+MAXRESULTS;

请注意,限制结果数量是一个好主意.